Two objects are attracted to each other with 36 N of gravitational force. What would the force between them be if the distance between them were doubled?

sg101cp6vv
2022-05-10
Answered

Two objects are attracted to each other with 36 N of gravitational force. What would the force between them be if the distance between them were doubled?

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Cara Cannon

Answered 2022-05-11
Author has **14** answers

Step 1

The gravitational force between two objects = 36 N

Let the mass of two objects be = m and M respectively

Let the distance between two objects = d

Step 2

Using Newton's law of gravitation :

Gravitational force = $G\times m\times M/{d}^{2}$

$36=G\times m\times M/{d}^{2}$

The gravitational force follows inverse square law that is it varies inversely with the square of distance between two objects.

Thus, if we double the distance between the two objects, the gravitational force would decrease by a factor of 4.

Hence, new gravitational force between the two objects after doubling the distance between them = 36/4

= 9 Newton

The gravitational force between two objects = 36 N

Let the mass of two objects be = m and M respectively

Let the distance between two objects = d

Step 2

Using Newton's law of gravitation :

Gravitational force = $G\times m\times M/{d}^{2}$

$36=G\times m\times M/{d}^{2}$

The gravitational force follows inverse square law that is it varies inversely with the square of distance between two objects.

Thus, if we double the distance between the two objects, the gravitational force would decrease by a factor of 4.

Hence, new gravitational force between the two objects after doubling the distance between them = 36/4

= 9 Newton

asked 2022-05-19

I have this expression for the gravitational force between 2 masses when the gr term is added:

$F=-\frac{GMm}{{r}^{2}}+\frac{4{G}^{2}mM(M+m)}{{r}^{4}{c}^{2}}$

which I got from the internet since I haven't bee able to find a similar expression in any book. But i'm not sure if it's right or needs fixing.

Is the second term in the force correct?

$F=-\frac{GMm}{{r}^{2}}+\frac{4{G}^{2}mM(M+m)}{{r}^{4}{c}^{2}}$

which I got from the internet since I haven't bee able to find a similar expression in any book. But i'm not sure if it's right or needs fixing.

Is the second term in the force correct?

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Suppose the centre of mass of 2 bodies coincide , then how will we calculate the gravitational force between the 2 bodies ?

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I have heard that no one escape from the intense gravitational field of a black hole (obviously that's why it is black). And gravitational force is due to the mass having the body, no mass no gravity, as

$F=GMm/{r}^{2}$

Putting 0 in one of the two bodies' masses, gives no gravitational force. But light cannot escape from black hole due to its strong gravity, does that mean that light has mass? please correct me.

$F=GMm/{r}^{2}$

Putting 0 in one of the two bodies' masses, gives no gravitational force. But light cannot escape from black hole due to its strong gravity, does that mean that light has mass? please correct me.

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asked 2022-04-07

A satellite of the Earth has a mass of 100 kg and is at an altitude of $2.00\times {10}^{6}\text{}m$

(a) What is the gravitational potential energy of the satellite-Earth system?

(b) What is the magnitude of the gravitational force exerted by the Earth on the satellite?

(c) What force does the satellite exert on the Earth?

(a) What is the gravitational potential energy of the satellite-Earth system?

(b) What is the magnitude of the gravitational force exerted by the Earth on the satellite?

(c) What force does the satellite exert on the Earth?