Question regarding calculating acceleration due to gravity on planet Mercury

I was asked to calculate the acceleration due to gravity on planet Mercury, if the mas of Mercury is $2,99\times {10}^{22}kg$ and its radius is $2,42\times {10}^{3}\text{}km$. The mass of the object is $10kg$ and the mass of Earth is $6\times {10}^{24}kg$ and the Radius of the Earth is $3,82\times {10}^{3}km$

This question rather puzzled me because I was not sure if my answer is correct or not but let me proceed :

$\overrightarrow{F}=m\overrightarrow{a}={F}_{g}=G\frac{{m}_{1}{m}_{2}}{{r}^{2}}$

${m}_{1}g=G\frac{{m}_{1}{m}_{2}}{{r}^{2}}$

(Note that ${m}_{2}$ = mass of mercury)

$g=\frac{(6.673\times {10}^{-11}\frac{{m}^{2}}{k{g}^{2}})(2,99\times {10}^{22}kg)}{(2,42\times {10}^{6}\text{}m{)}^{2}}$

I compute my answer to be $0.34\frac{m}{{s}^{2}}$

What really is confusing me is that when I look at my textbook, it shows me the gravitational acceleration due to gravity on mercury to be $3.59\frac{m}{{s}^{2}}$

Can someone please explain to me what the answer that I am getting is giving me? My computation was marked correct in a test but I do not understand what this value is giving me.

I was asked to calculate the acceleration due to gravity on planet Mercury, if the mas of Mercury is $2,99\times {10}^{22}kg$ and its radius is $2,42\times {10}^{3}\text{}km$. The mass of the object is $10kg$ and the mass of Earth is $6\times {10}^{24}kg$ and the Radius of the Earth is $3,82\times {10}^{3}km$

This question rather puzzled me because I was not sure if my answer is correct or not but let me proceed :

$\overrightarrow{F}=m\overrightarrow{a}={F}_{g}=G\frac{{m}_{1}{m}_{2}}{{r}^{2}}$

${m}_{1}g=G\frac{{m}_{1}{m}_{2}}{{r}^{2}}$

(Note that ${m}_{2}$ = mass of mercury)

$g=\frac{(6.673\times {10}^{-11}\frac{{m}^{2}}{k{g}^{2}})(2,99\times {10}^{22}kg)}{(2,42\times {10}^{6}\text{}m{)}^{2}}$

I compute my answer to be $0.34\frac{m}{{s}^{2}}$

What really is confusing me is that when I look at my textbook, it shows me the gravitational acceleration due to gravity on mercury to be $3.59\frac{m}{{s}^{2}}$

Can someone please explain to me what the answer that I am getting is giving me? My computation was marked correct in a test but I do not understand what this value is giving me.