When sodium is bombarded with electrons accelerated through a potential difference <mi mathvaria

anniferathonniz8km

anniferathonniz8km

Answered question

2022-05-10

When sodium is bombarded with electrons accelerated through a potential difference Δ V, its x-ray spectrum contains emission peaks at 1.04 keV and 1.07 keV. Find the minimum value of Δ V required to produce both of these peaks.

Answer & Explanation

Cristal Obrien

Cristal Obrien

Beginner2022-05-11Added 16 answers

The equation for the energy required to produce the peaks is given by,
E = e Δ V
Here, E is the energy peak, e is the charge of the electron and AV is the potential difference required.
Rewriting the above equation,
Δ V = E e
Substitute the numerical value in the equation to find the value of Δ V corresponding to 1.04keV.
Δ V = 1.04   k e V e = 1.04   k V
Substitute the numerical value in the equation to find the value of Δ V corresponding to 1.07 keV.
Δ V = 1.07   k e V e = 1.07   k V

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