# The first member of Balmer series of hydrogen atom has

quorums15lep 2022-05-10 Answered
The first member of Balmer series of hydrogen atom has a wavelength of 6561 Å. Find wavelength of the second member of the Balmer series (in nm)
You can still ask an expert for help

Expert Community at Your Service

• Live experts 24/7
• Questions are typically answered in as fast as 30 minutes
• Personalized clear answers

Solve your problem for the price of one coffee

• Available 24/7
• Math expert for every subject
• Pay only if we can solve it

## Answers (1)

Duncan Cox
Answered 2022-05-11 Author has 18 answers
The first member of the Balmer series of hydrogen atom has a wavelength of 6561 Å.
We have to find,
Wavelength of the second member of the Balmer series (in nm)
We know,
$\mathrm{△}E=\frac{hc}{\lambda }=\mathrm{△}{E}_{0}\left[\frac{1}{4}-\frac{1}{9}\right]$
So,
###### Not exactly what you’re looking for?

Expert Community at Your Service

• Live experts 24/7
• Questions are typically answered in as fast as 30 minutes
• Personalized clear answers

Solve your problem for the price of one coffee

• Available 24/7
• Math expert for every subject
• Pay only if we can solve it