The first member of Balmer series of hydrogen atom has

quorums15lep 2022-05-10 Answered
The first member of Balmer series of hydrogen atom has a wavelength of 6561 Å. Find wavelength of the second member of the Balmer series (in nm)
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Answers (1)

Duncan Cox
Answered 2022-05-11 Author has 18 answers
The first member of the Balmer series of hydrogen atom has a wavelength of 6561 Å.
We have to find,
Wavelength of the second member of the Balmer series (in nm)
We know,
E = h c λ = E 0 [ 1 4 1 9 ]
So,
h c λ = E 0 [ 1 4 1 16 ] χ λ = 5 × 16 9 × 4 × 3 λ = 5 × 4 × 656.1 9 × 3 = 486   n m
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