When a 120 V potential difference is applied across a $30\mathrm{\Omega}$ resistance of electric device. What is the current through the electric device? What is the power of the electric device?

lifretatox8n
2022-05-10
Answered

When a 120 V potential difference is applied across a $30\mathrm{\Omega}$ resistance of electric device. What is the current through the electric device? What is the power of the electric device?

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odvucimo1pp17

Answered 2022-05-11
Author has **23** answers

Apply Ohm's Law

voltage = Resistance $\times $ Current

U=RI

The voltage is U=120V

The resistance is $R=30\mathrm{\Omega}$

The current is

$I=\frac{U}{R}=\frac{120}{30}=4A$

The power is

P=UI=120*4=480W

voltage = Resistance $\times $ Current

U=RI

The voltage is U=120V

The resistance is $R=30\mathrm{\Omega}$

The current is

$I=\frac{U}{R}=\frac{120}{30}=4A$

The power is

P=UI=120*4=480W

Stoyanovahvsbh

Answered 2022-05-12
Author has **3** answers

We first find the current flowing through the device using Ohm's law, which is:

V=IR

I is the current in amperes

R is the resistance in ohms

And so,

$120V=I\ast 30\mathrm{\Omega}$

$I=\frac{120V}{30\mathrm{\Omega}}$

=4A

To find the power, we use the equation,

P=IV

So, the power here is:

P=4A*120V

=480W

V=IR

I is the current in amperes

R is the resistance in ohms

And so,

$120V=I\ast 30\mathrm{\Omega}$

$I=\frac{120V}{30\mathrm{\Omega}}$

=4A

To find the power, we use the equation,

P=IV

So, the power here is:

P=4A*120V

=480W

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