3c4ar1bzki1u
2022-05-08
Answered

How would you use permutations to find the arrangements possible if a line has 4 girls and 4 boys alternating boy girl boy girl?

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bamenyab4mxn

Answered 2022-05-09
Author has **16** answers

Step 1

Line of 4 boys: $4\times 3\times 2\times 1=4!=24$ possibilities.

Line of 4 girls: also $4!=24$ possibilities.

Step 2

Combination of the two: $4!\times 4!={24}^{2}=576$ posibilities.

If it doesn't matter whether the first is a boy or a girl, we'll have to double that to $2\times 576=1152$

Line of 4 boys: $4\times 3\times 2\times 1=4!=24$ possibilities.

Line of 4 girls: also $4!=24$ possibilities.

Step 2

Combination of the two: $4!\times 4!={24}^{2}=576$ posibilities.

If it doesn't matter whether the first is a boy or a girl, we'll have to double that to $2\times 576=1152$

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