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Logan Lamb 2022-05-09 Answered
If α, β, γ, δ are smallest positive angle in ascending order of magnitude which have their sines equal to positive quantity λ , then if
4 sin α 2 + 3 sin β 2 + 2 sin γ 2 + sin δ 2 = 2 1 + λ
then λ = ?
Options-
(1) sin α
(2) sin β
(3) sin γ
(4) sin δ
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Answers (1)

percolarse2rzd
Answered 2022-05-10 Author has 17 answers
See we have ascending order for positive sines as a , π a , 2 π + a , 3 π a as sine is positive only in first two quadrants .Now these are values of α , β , γ , δ plugging in and simplifying we get sin ( α / 2 ) + cos ( α / 2 ) = 1 + λ thus squaring we get λ = sin ( α )
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