Samples are taken from two different types of honey and the viscosity is measured.

Honey A:

Mean: 114.44

S.D : 0.62

Sample Size: 4

Honey B:

Mean: 114.93

S.D: 0.94

Sample Size: 6

Assuming normal distribution, test at 5% significance level whether there is a difference in the viscosity of the two types of honey?

Here's what I did:

I took my null hypothesis as $\mu $B - $\mu $A = 0 and alternative hypothesis as $\mu $B - $\mu $A $\ne $ 0

Then I did my calculations which were as following:

Test Statistic = (B -A ) - ($\mu $B - $\mu $A) / sqrt {(variance B / sample size B) + (variance A / sample size A)}

This gave me test statistic as = 0.49/0.49332 that is equal to 0.993

However the test statistic in the book solution is given as 0.91. What am I doing wrong?

Honey A:

Mean: 114.44

S.D : 0.62

Sample Size: 4

Honey B:

Mean: 114.93

S.D: 0.94

Sample Size: 6

Assuming normal distribution, test at 5% significance level whether there is a difference in the viscosity of the two types of honey?

Here's what I did:

I took my null hypothesis as $\mu $B - $\mu $A = 0 and alternative hypothesis as $\mu $B - $\mu $A $\ne $ 0

Then I did my calculations which were as following:

Test Statistic = (B -A ) - ($\mu $B - $\mu $A) / sqrt {(variance B / sample size B) + (variance A / sample size A)}

This gave me test statistic as = 0.49/0.49332 that is equal to 0.993

However the test statistic in the book solution is given as 0.91. What am I doing wrong?