22 Kaif Hakim

22 Kaif Hakim

Answered question

2022-05-12

 

Answer & Explanation

Nick Camelot

Nick Camelot

Skilled2023-05-07Added 164 answers

Given, mean μ=100, standard deviation σ=16, and the distribution of IQ is assumed to be normal.
To find the percentage of children having IQ between 70 and 120, we need to find the corresponding z-scores and use the standard normal distribution table.
First, we find the z-score for IQ of 70:
z1=7010016=1.875
Next, we find the z-score for IQ of 120:
z2=12010016=1.25
Using the given areas for the standard normal distribution, we have:
P(1.875<Z<1.25)=P(Z<1.25)P(Z<1.875)=0.39440.0304=0.3640
Therefore, the percentage of children having IQ between 70 and 120 is:
0.3640×100%=36.40%
Thus, the solution is completed.

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