Maximize <msub> x 2 </msub> &#x2212;<!-- − --> <msub> x 1 </m

estroishave4

estroishave4

Answered question

2022-05-02

Maximize
x 2 x 1 + y 1 y 2
given that x 1 2 + y 1 2 = 1 and x 2 2 + y 2 2 = 1.
I was thinking about using Lagrange multipliers, but I only know how that works for a 3-variable function, not 4. Could someone please suggest a way to solve this? Maybe with Lagrange multipliers or some more elementary method?

Answer & Explanation

Daisy Patrick

Daisy Patrick

Beginner2022-05-03Added 16 answers

y 1 x 1 y 1 2 + x 1 2 1 + 1 = 2 . Similarly x 2 y 2 2 so the given expession does not exceed 2 2 . To see that this value is actually attained take x 1 = 1 2 , y 1 = 1 2 x 2 = 1 2 and y 2 = 1 2 .
utloverej

utloverej

Beginner2022-05-04Added 15 answers

By the hypotesis you can write x 1 = sin θ , y 1 = cos θ and x 2 = sin α , y 2 = cos α. Then, your want to find the maximum value of
E = ( sin α sin θ ) + ( cos α cos θ ) = ( sin α + cos α ) ( sin θ + cos θ ) .
But, 2 sin x + cos x 2 ,   x [ 0 , 2 π ] and the equality holds for α = π / 4 and θ = 5 π / 4. In particular, E 2 2 , exactly as professor Rama Murty found.

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