Show that 5\cos^2x-2\sqrt{3}\sin x\cos x+3\sin^2x=\cos2x-\sqrt{3}\sin2x+4

bacfrancaiso0j

bacfrancaiso0j

Answered question

2022-05-03

Show that 5cos2x23sinxcosx+3sin2x=cos2x3sin2x+4

Answer & Explanation

RormFrure6h1

RormFrure6h1

Beginner2022-05-04Added 13 answers

Notice, the following formula
cos2A+sin2A=1
2sinAcosA=sin2A
cos2Asin2A=cos2A
Now, we have
LHS=5cos2x23sinxcosx+3sin2x
=4cos2x+cos2x3(2sinxcosx)+4sin2xsin2x
=4(cos2x+sin2x)3sin2x+(cos2xsin2x)
=4(1)3sin2x+(cos2x)
=cos2x3sin2x+4=RHS

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?