Repeating decimals in converted fractions, why these increments? a)

svezic0rn

svezic0rn

Answered question

2022-03-31

Repeating decimals in converted fractions, why these increments?
a) 131=0.032258064516129 ., the repetend is 032258064516129 which can be broken into the numbers 032258, 064516, 129032 that are related by multiples of 2:
b) 113=0.076923. , the repetend is 076923 which can be broken into 0769, 2307 that are related by multiplying by 3:
c) 117=0.0588235294117647 , the repetend is 0588235294117647 which can be broken into the numbers 5882352941, 11764705882 that are related by multiplying by 2:
d) 119=0.052631578947368421 , the repetend is 052631578947368421 which can be broken into the numbers 05263 , 15789 , 47367 , 142101 (think of the initial 1 in 142101 being removed from the 8 in the preceding 47368) that are related by multiples of 3:
e) 121=0.047619 , the repetend is 047619 which can be broken into the numbers 0476, 1904 that are related by multiplying by 4:

Answer & Explanation

Nathanial Carey

Nathanial Carey

Beginner2022-04-01Added 12 answers

Step 1
The first thing to think about is finding the repeating decimal by long division. Taking 117 for example, your first division starts with a remainder 1. You append a 0 to it and try to divide 17 into 10. It goes 0 times, which gives the leading 0 in the repeat. You then pass a remainder of 10 to the next digit. You pull down another 0, getting 100, divide 17 into it getting 5 with a remainder of 15. The 5 is the second digit of the repeat and the 15 goes on for the next digit.
If you have a full length repeat like 17, you must use each of the remainders from 1 to 171 once. When you repeat a remainder you have finished the repeat. For 13, which has only a six digit repeat you only use six remainders. This explains all the relationships you show.
After the nth digit the remainder is 10nmod17. We can find that 10102±mod17 That means after 10 digits you pass a remainder of 2 to the next digit. The repeat from there will clearly be twice the repeat starting from the front, where the remainder is 1.

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