Proving the generator of A = \{154a + 210b : a,b

Rowan Huynh 2022-04-30 Answered

Proving the generator of

A = {154 a + 210 b : a, b \in Z}

is

(154, 210)

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Answers (1)

August Moore

Answered 2022-05-01 Author has 17 answers

Step 1
For the further proof , you just need to show that

154 a + 210 b

just generates all the common multiples of 154 and 210 for different values of a and b where

a, b \in Z

and even HCF can also be written in in the form

154 a + 210 b

for a particular choice of a and b . And HCF obviously generate all the common multiples then.

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