Proving the generator of A = \{154a + 210b : a,b

Rowan Huynh 2022-04-30 Answered
Proving the generator of
A={154a+210b:a,bZ} is (154, 210)
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Answers (1)

August Moore
Answered 2022-05-01 Author has 17 answers
Step 1
For the further proof , you just need to show that
154a+210b
just generates all the common multiples of 154 and 210 for different values of a and b where
a, bZ
and even HCF can also be written in in the form
154a+210b
for a particular choice of a and b . And HCF obviously generate all the common multiples then.
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