Limit of \cos(kt+kux) as k \to 0 where k=2\sqrt{1-a^2} u=b(6-k^2) and a and b

Deven Livingston 2022-04-29 Answered
Limit of cos(kt+kux) as k0
where
k=21a2
u=b(6k2)
and a and b are real numbers?
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Answers (1)

Olive Guzman
Answered 2022-04-30 Author has 16 answers
For small cos(z)1z22. For small k,u6b. Then
cos(k(x+6bt))1k22(t+6xb)2
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