I have this integral to evaluate: \(\displaystyle\int{7}^{{{2}{x}+{3}}}{\left.{d}{x}\right.}\)

Rex Maxwell

Rex Maxwell

Answered question

2022-04-01

I have this integral to evaluate: 72x+3dx

Answer & Explanation

enriuadaziaa

enriuadaziaa

Beginner2022-04-02Added 7 answers

You can always differentiate to be sure:
ddx72x+32ln7=12ln7ddx72x+3=12ln7(ln7)72x+3ddx(2x+3)=72x+3
Your result is sort of right; you're missing the constant and the differential after the substitution should be du, so the result is the following:
72x+3dx=127udu=72x+32ln7+C

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