I have \(\displaystyle{\frac{{{\tan{{15}}}^{\circ}}}{{{1}-{\tan{{15}}}^{\circ}^{2}}}}\)

acidizihvzs

acidizihvzs

Answered question

2022-04-01

I have
tan15°1-tan152

Answer & Explanation

Jared Kemp

Jared Kemp

Beginner2022-04-02Added 14 answers

2tan(15)1tan(15)2=tan(30)=13 (1)
because:
tan(α)+tan(β)1tan(α)tan(β)=tan(α+β)
Following equation (1):
tan(15)1tan(15)2=12tan(30)=123
And finally we employ a very useful method in dealing with roots, multiplying by 1:
123=123×33=36

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