How would you solve: \(\displaystyle{2}{{\csc}^{{2}}{x}}={3}{{\cot}^{{2}}{x}}-{1}\)

Anahi Solomon

Anahi Solomon

Answered question

2022-03-31

How would you solve:
2csc2x=3cot2x1

Answer & Explanation

delai59qk

delai59qk

Beginner2022-04-01Added 8 answers

2csc2x=3(csc2x1)1=3csc2x4
csc2x4=0
1sin2x=4
sin2x=14
x=kπ±π6
haiguetenteme7zyu

haiguetenteme7zyu

Beginner2022-04-02Added 13 answers

Notice, we can also solve this as follows
2csc2x=3cot2x1
2sin2x=3cos2xsin2x1
2=3cos2xsin2x
3cos2x(1cos2x)=2
4cos2x=3
cos2x=34=(32)2
cos2x=(cosπ6)2
Now, writing the general solution as follows

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