How to solve this quadratic equation (with x

ICESSRAIPCELOtblt

ICESSRAIPCELOtblt

Answered question

2022-03-31

How to solve this quadratic equation (with x represented by a fraction containing a square root)?
If x45=±315, how can I find the values of a and b in the following equation?
5x2+ax+b=0?
I've tried substituting (45±315) for x and got totally confused there.

Answer & Explanation

Ashton Conrad

Ashton Conrad

Beginner2022-04-01Added 11 answers

Square both sides, multiply both sides by 5, then move all terms to the left side. Note that your original equation is really two equations, but after squaring they are the same:
x45=±315  (x45)2=(±315)2   x285x+1625=3125   5x28x+165=315   5x28x155=0   5x28x3=0.
So a=8 and b=3.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?