Solve this trigonometric inequality: \(\displaystyle{\sin{{x}}}{\sin{{2}}}{x}-{\cos{{x}}}{\cos{{2}}}{x}{>}{\sin{{6}}}{x}\)

Coradossi7xod

Coradossi7xod

Answered question

2022-03-23

Solve this trigonometric inequality:
sinxsin2xcosxcos2x>sin6x

Answer & Explanation

Jonathon Hanson

Jonathon Hanson

Beginner2022-03-24Added 9 answers

My steps:
cosxcos2xsinxsin2x<sin6x
cos3x<sin(6x)
cos3x<cos(π2+6x)
From this we get:
3x>π2+6x+2kπ
3x>π2+2kπ
x<π6+2kπ3
and 3x<π26x+2kπ
9x<π2+2kπ
x<π18+2kπ9

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