Solve this inequality \frac{1}{x^2-14x+40}\leq0

predorsomwy 2022-04-26 Answered
Solve this inequality
1x214x+400
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Answers (1)

Giovanny Howe
Answered 2022-04-27 Author has 18 answers
Given:
1x214x+400
Factorising the term x214+40
Let p(x)=x214x+40
=x24x10x+40
=x(x4)10(x4)
=(x10)(x4)
p(x)=0 when x=(10,4)
p(x)>0 when x(,4)
p(x)<0 when x(4,10)
p(x)>0 when x(10,)
For 1x214x+400
x214x+40 should be less that 0. Thus, the solution is (4,10)
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