Solve the equation \(\displaystyle{z}^{{3}}-{2}{z}^{{2}}+{3}{z}-{2}={0}.\) If a is a

Reuben Brennan

Reuben Brennan

Answered question

2022-03-21

Solve the equation z32z2+3z2=0.
If a is a complex solution of this equation, what does A equal?
A=|a|21i43

Answer & Explanation

alwadau8ndv

alwadau8ndv

Beginner2022-03-22Added 9 answers

Since |z1|=|z2|=(12)2+(±72)2=2 and i43=(i2)21i=i we have
A=|a|21+i=21+i=21+i×1i1i=2(1i)2=1i.
Cason Singleton

Cason Singleton

Beginner2022-03-23Added 13 answers

Hint: z32z2+3z2=(z1)(z2z+2). You get the complex (I mean non-real) roots by solving then quadratic z2z+2=0.

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