Solve \(\displaystyle{\tan{{x}}}{\cos{{2}}}{x}={\frac{{{1}}}{{{5}}}}\) for \(\displaystyle{0}^{\circ}{ < }{x}{

ezpimpin6988ok1n

ezpimpin6988ok1n

Answered question

2022-03-21

Solve tanxcos2x=15 for 0<x<360
Can I get some hints for solving this trigonometry equation?

Answer & Explanation

Theodore Davila

Theodore Davila

Beginner2022-03-22Added 14 answers

Putting t=tanx:
t1t21+t2=15
5t3+t25t+1=0
t=1.1857,0.22043,0.76524
etc.
Brennan Thompson

Brennan Thompson

Beginner2022-03-23Added 10 answers

You can try using the identity tan2x+1=sec2x and that cos2x=2cos2x1:
t(2c21)=15
t(2t2+11)=15

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