# You intend to estimate a population mean with a confidence interval. You believe the population to have a normal distribution. Your sample size is 28.

You intend to estimate a population mean with a confidence interval. You believe the population to have a normal distribution. Your sample size is 28. Find the critical value that corresponds to a confidence level of 98%. (Report answer accurate to three decimal places with appropriate rounding.) $t\frac{a}{2}=$

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nitruraviX
Here, $n=28$ and confidence level is 0.98. The level of significance is 0.02. The degrees of freedom is 27 $\left(=n-1\right)$. Using Excel formula $“=T.INV\left(1-\left(\frac{0.02}{2}\right),27\right)”.$ the critical value that corresponds to a confidence level of 98% is 2.473 (rounded to three decimals). $t\frac{a}{2}=2.473.$