Help showing \(\displaystyle{\int_{{0}}^{{1}}}{\frac{{{\left.{d}{x}\right.}}}{{{x}{\log{{\frac{{{1}}}{{{x}}}}}}}}}\) is unbounded

zatajuxoqj

zatajuxoqj

Answered question

2022-03-27

Help showing 01dxxlog1x is unbounded

Answer & Explanation

aznluck4u72x4

aznluck4u72x4

Beginner2022-03-28Added 16 answers

01dxlogx=0dtt, where t=logx, and the latter integral surely diverges (at both ends) (as the primitive function is log|t|)
the divergence at x=0 probably needs this substitution. The divergence at 1 is clear without any substitution - your function there behaves as cx1

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