Fractions and roots I have this problem: \(\displaystyle{\frac{{\sqrt{{{18}}}+\sqrt{{{98}}}+\sqrt{{{50}}}+{4}}}{{{2}\sqrt{{{2}}}}}}\) I'm able

Dumaen80p3

Dumaen80p3

Answered question

2022-03-24

Fractions and roots
I have this problem:
18+98+50+422
I'm able to get to this part by myself:
152+222
But that's when I get stuck. The book says that the next step is:
15222+222
But I don't understand why you can take the 2 out of the original fraction, make it the numerator of its own fraction and having root of 2 as the denominator of said fraction.

Answer & Explanation

anghoelv1lw

anghoelv1lw

Beginner2022-03-25Added 19 answers

18+98+50+422=32+72+52+422=152+422
Now the standard procedure is to remove the radical in the denominator:
152+422=152+42222=152·2+4222·2=30+424=15+222
One can do it differently: set a=2, so you can write
152+422=15a+a4a3=15+a3a2=15+222
The final result can also be written by using a+bc=ac+bc so
15+222=152+2
Whether you want to do this last transformation depends on what you have to do with this number.

Madilyn Shah

Madilyn Shah

Beginner2022-03-26Added 11 answers

To me the next obvious step is to remove the radical in the denominator so
152+222=15+22.
Personally I would stop there, but you could separate this into 152+22 or into 152+12 if you really wanted to.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?