If \sqrt{36}=6 is true, then why is \sqrt{36}=-6 false in

If $\sqrt{36}=6$ is true, then why is $\sqrt{36}=-6$ false in verification of radical equations?
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jeffster830gyz
If $36=\left(+6\right)\left(+6\right)=\left(-6\right)\left(-6\right)$
Then $\sqrt{36}=\sqrt{|36|}=±6$
But when you have an equation is needed to accept both results.
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Landyn Whitney
In general notation, $\sqrt{a}=$ the positive (+) square root and $-\sqrt{a}=$ the negative (-) square root. So, in the instant case, .