My task is to evaluate \sin(-\frac{\pi}{6}+\frac{1}{2}\arccos(\frac{1}{3}))

sexe4yo

sexe4yo

Answered question

2022-04-21

My task is to evaluate
sin(π6+12arccos(13))

Answer & Explanation

Patricia Duffy

Patricia Duffy

Beginner2022-04-22Added 16 answers

let
cos1(13)=t
then we know that
0<t<π2,cost=13,cos(t2)=1+cost2=23,sin(t2)=13
now we can evaluate
sin(π6+t2)=sin(t2)cos(π6)cos(t2)sin(π6)
=13342314=1216

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