How to find: \lim_{x \to \frac{\pi}{2}} \frac{\tan{2x}}{x - \frac{\pi}{2}}

p3sa1bynn 2022-04-21 Answered
How to find:
limxπ2tan{2x}xπ2
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Answers (1)

Waylon Padilla
Answered 2022-04-22 Author has 19 answers

Put x=π2+h. As xπ2, you have h0
Then you have
limxπ2tan2xxπ2=limh0tan2(π2+h)h
=limh0tan(π+2h))h
=limh0tan(2h)h
Can you do it from here?

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