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Put x=π2+h. As x→π2, you have h→0Then you havelimx→π2tan2xx−π2=limh→0tan2(π2+h)h=limh→0tan(π+2h))h=limh→0tan(2h)hCan you do it from here?
The figure shows the surface created when the cylinder y2+Z2=1 intersects the cylinder x2+Z2=1. Find the area of this surface.The figure is something like:
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