How to find out what remainder will (x-1)^{2013} have upon

Bronson Olson

Bronson Olson

Answered question

2022-04-21

How to find out what remainder will (x1)2013 have upon division by x22x+2

Answer & Explanation

Jayla Matthews

Jayla Matthews

Beginner2022-04-22Added 18 answers

For even (an1)=(a+1)(an1an2++a1).
For a=(x1)2 and n=1006:
(x1)20121=
[(x1)2+1][(x1)2010(x1)2008+(x1)2006+(x1)21]
(x1)2013(x1)
=[(x1)2+1][(x1)2011(x1)2009+(x1)2007+(x1)3(x1)]
(x1)2013=(x22x+2)()+(x1)

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