How to evaluate \lim_{x \to 0} \frac{x^2\sin {\frac{1}{x}}}{\sin x}

Ricardo Berger

Ricardo Berger

Answered question

2022-04-21

How to evaluate limx0x2sin{1x}sinx

Answer & Explanation

ritmesysv

ritmesysv

Beginner2022-04-22Added 12 answers

Just observe that
|x2sin{1x}|x2
giving, as x0,
|x2sin{1x}sinx|x2|sinx|=|xsinx|×|x|1×0=0

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