Verify that the function is a solution to the differential equation u(t)=e^{t^2}\int^t_0e^{-s

Dania Robbins

Dania Robbins

Answered question

2022-04-19

Verify that the function is a solution to the differential equation
u(t)=et20tes2ds+et2
is a particular solution to the differential equation:
du dt 2tu=1
My Attempt
I will verify this by differentiating the function with respect to t.
dudt=ddt(et20tes2ds+et2) =2tet2(0tes2ds)+et2ddt(0tes2ds)+2tet2
I'm having trouble solving the integral because it involves an error function. Could I get some pointers on how to evaluate this? Or is there a different way to verify that the function is a solution?

Answer & Explanation

Trey Harrington

Trey Harrington

Beginner2022-04-20Added 10 answers

You do not need to integrate the function, you can use Leibniz Integral rule
Then du dt  becomes
dudt=ddt(et20tes2ds+et2)
=2tet2(0tes2ds)+et2ddt(0tes2ds)+2tet2=2tet2(0tes2ds)+et2et2+2tet2
=2t(et20te-s2ds+et2)+1=2tu+1
Hence du dt 2tu=1.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?