Solve \tan^{-1}(\frac{1-x}{1+x})=\frac{1}{2}\tan^{-1}(x)

Jazmine Sweeney

Jazmine Sweeney

Answered question

2022-04-20

Solve
tan1(1x1+x)=12tan1(x)

Answer & Explanation

Daisy Patrick

Daisy Patrick

Beginner2022-04-21Added 16 answers

arctan1x1+x=12arctanxarctantan(π4arctan(x))=12arctanx
So:
π4=32arctanxarctanx=π6x=tan(π6)
=13

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