What is a general solution to the differential equation 1+y^{2}=y'\sqrt{1-x^{2}}=0?

alahovom7ahc

alahovom7ahc

Answered question

2022-04-16

What is a general solution to the differential equation 1+y2=y1x2=0?

Answer & Explanation

Quimpoah3b

Quimpoah3b

Beginner2022-04-17Added 13 answers

Explanation:
1+y2y1x2=0
first we separate it
1+y2=y1x2
11+y2y=11x2
then integrate
11+y2ydx=11x2dx
11+y2dy=11x2dx
these are standard integrals, done using tan and sin subs, which means....
tan1y=sin1x+C
y=tan(sin1x+C)

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