How do you find the equation of the

Lillianna Sandoval

Lillianna Sandoval

Answered question

2022-04-18

How do you find the equation of the tangent line to the curve y=sin(sinx) at (π,0)?

Answer & Explanation

ysnlm8eut

ysnlm8eut

Beginner2022-04-19Added 14 answers

If we take the derivative, we get by the chain rule that
t=cos(sinx)cosx
At x=π this takes the value of
y(π)=cos(sinπ)cos(π)=cos(0)(1)=1
Therefore the equation of the tangent is
yy1=m(xx1)
y0=1(xπ)
y=x+π

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