Find the solution of the equation
rounded to two decimals.
1) \(\displaystyle{3.02}{x}+{1.48}={10.92}\)
2) \(\displaystyle{8.36}-{0.95}{x}={9.97}\)
3) \(\displaystyle{2.15}{x}-{4.63}={x}+{1.19}\)
Step 1
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Step 2
1) \(\displaystyle{3.02}{x}+{1.48}={10.92}\)
we have to find the solution of the equation rounded to two decimals.
the given equation is \(\displaystyle{3.02}{x}+{1.48}={10.92}\)

\(\displaystyle{3.02}{x}+{1.48}={10.92}\)

\(\displaystyle{3.02}{x}+{1.48}-{1.48}={10.92}-{1.48}\)

PSK3.02x=9.44

\(\displaystyle{\frac{{{3.02}{x}}}{{{3.02}}}}={\frac{{{9.44}}}{{{3.02}}}}\)

\(\displaystyle{x}={3.12582781}\) therefore value of x is 3.12582781 therefore the value of x rounded to two decimals is 3.13 therefore the solution of the equation rounded to two decimals is 3.13 Step 3 2) \(\displaystyle{8.36}-{0.95}{x}={9.97}\) we have to find the solution of the equation rounded to two decimals. the given equation is \(\displaystyle{8.36}-{0.95}{x}={9.97}\)

\(\displaystyle{8.36}-{0.95}{x}={9.97}\)

\(\displaystyle{8.36}-{0.95}{x}-{8.36}={9.97}-{8.36}\)

\(\displaystyle-{0.95}{x}={1.61}\)

\(\displaystyle{\frac{{-{0.95}{x}}}{{-{0.95}}}}={\frac{{{1.61}}}{{-{0.95}}}}\)

\(\displaystyle{x}={\frac{{-{1.61}}}{{{0.95}}}}\)

\(\displaystyle{x}=-{1.69473684}\) therefore value of x is -1.69473684 therefore the value of x rounded to two decimals is -1.69 therefore the solution of the equation rounded to two decimals is -1.69 Step 4 3) \(\displaystyle{2.15}{x}-{4.63}={x}+{1.19}\) we have to find the solution of the equation rounded to two decimals. the given equation is \(\displaystyle{2.15}{x}-{4.63}={x}+{1.19}\)

\(\displaystyle{2.15}{x}-{4.63}={x}+{1.19}\)

\(\displaystyle{2.15}{x}-{x}-{4.63}={x}-{x}+{1.19}\)

\(\displaystyle{1.15}{x}-{4.63}={1.19}\)

\(\displaystyle{1.15}{x}-{4.63}+{4.63}={1.19}+{4.63}\)

\(\displaystyle{1.15}{x}={5.82}\)

\(\displaystyle{\frac{{{1.15}{x}}}{{{1.15}}}}={\frac{{{5.82}}}{{{1.15}}}}\)

\(\displaystyle{x}={5.06086957}\) therefore value of x is 5.06086957 therefore the value of x rounded to two decimals is 5.06 therefore the solution of the equation rounded to two decimals is 5.06

\(\displaystyle{3.02}{x}+{1.48}={10.92}\)

\(\displaystyle{3.02}{x}+{1.48}-{1.48}={10.92}-{1.48}\)

PSK3.02x=9.44

\(\displaystyle{\frac{{{3.02}{x}}}{{{3.02}}}}={\frac{{{9.44}}}{{{3.02}}}}\)

\(\displaystyle{x}={3.12582781}\) therefore value of x is 3.12582781 therefore the value of x rounded to two decimals is 3.13 therefore the solution of the equation rounded to two decimals is 3.13 Step 3 2) \(\displaystyle{8.36}-{0.95}{x}={9.97}\) we have to find the solution of the equation rounded to two decimals. the given equation is \(\displaystyle{8.36}-{0.95}{x}={9.97}\)

\(\displaystyle{8.36}-{0.95}{x}={9.97}\)

\(\displaystyle{8.36}-{0.95}{x}-{8.36}={9.97}-{8.36}\)

\(\displaystyle-{0.95}{x}={1.61}\)

\(\displaystyle{\frac{{-{0.95}{x}}}{{-{0.95}}}}={\frac{{{1.61}}}{{-{0.95}}}}\)

\(\displaystyle{x}={\frac{{-{1.61}}}{{{0.95}}}}\)

\(\displaystyle{x}=-{1.69473684}\) therefore value of x is -1.69473684 therefore the value of x rounded to two decimals is -1.69 therefore the solution of the equation rounded to two decimals is -1.69 Step 4 3) \(\displaystyle{2.15}{x}-{4.63}={x}+{1.19}\) we have to find the solution of the equation rounded to two decimals. the given equation is \(\displaystyle{2.15}{x}-{4.63}={x}+{1.19}\)

\(\displaystyle{2.15}{x}-{4.63}={x}+{1.19}\)

\(\displaystyle{2.15}{x}-{x}-{4.63}={x}-{x}+{1.19}\)

\(\displaystyle{1.15}{x}-{4.63}={1.19}\)

\(\displaystyle{1.15}{x}-{4.63}+{4.63}={1.19}+{4.63}\)

\(\displaystyle{1.15}{x}={5.82}\)

\(\displaystyle{\frac{{{1.15}{x}}}{{{1.15}}}}={\frac{{{5.82}}}{{{1.15}}}}\)

\(\displaystyle{x}={5.06086957}\) therefore value of x is 5.06086957 therefore the value of x rounded to two decimals is 5.06 therefore the solution of the equation rounded to two decimals is 5.06