# Find the solution of the equation rounded to two decimals. 1) 3.02x+1.48=10.92 2) 8.36-0.95x=9.97 3) 2.15x-4.63=x+1.19

Question
Decimals
Find the solution of the equation rounded to two decimals. 1) $$\displaystyle{3.02}{x}+{1.48}={10.92}$$ 2) $$\displaystyle{8.36}-{0.95}{x}={9.97}$$ 3) $$\displaystyle{2.15}{x}-{4.63}={x}+{1.19}$$

2021-03-13
Find the solution of the equation rounded to two decimals. 1) $$\displaystyle{3.02}{x}+{1.48}={10.92}$$ 2) $$\displaystyle{8.36}-{0.95}{x}={9.97}$$ 3) $$\displaystyle{2.15}{x}-{4.63}={x}+{1.19}$$ Step 1 “Since you have posted a question with multiple sub-parts, we will solve first three subparts for you. To get the remaining sub-parts solved, please repost the complete question and mention the sub-parts to be solved.”. Step 2 1) $$\displaystyle{3.02}{x}+{1.48}={10.92}$$ we have to find the solution of the equation rounded to two decimals. the given equation is $$\displaystyle{3.02}{x}+{1.48}={10.92}$$
$$\displaystyle{3.02}{x}+{1.48}={10.92}$$
$$\displaystyle{3.02}{x}+{1.48}-{1.48}={10.92}-{1.48}$$
PSK3.02x=9.44
$$\displaystyle{\frac{{{3.02}{x}}}{{{3.02}}}}={\frac{{{9.44}}}{{{3.02}}}}$$
$$\displaystyle{x}={3.12582781}$$ therefore value of x is 3.12582781 therefore the value of x rounded to two decimals is 3.13 therefore the solution of the equation rounded to two decimals is 3.13 Step 3 2) $$\displaystyle{8.36}-{0.95}{x}={9.97}$$ we have to find the solution of the equation rounded to two decimals. the given equation is $$\displaystyle{8.36}-{0.95}{x}={9.97}$$
$$\displaystyle{8.36}-{0.95}{x}={9.97}$$
$$\displaystyle{8.36}-{0.95}{x}-{8.36}={9.97}-{8.36}$$
$$\displaystyle-{0.95}{x}={1.61}$$
$$\displaystyle{\frac{{-{0.95}{x}}}{{-{0.95}}}}={\frac{{{1.61}}}{{-{0.95}}}}$$
$$\displaystyle{x}={\frac{{-{1.61}}}{{{0.95}}}}$$
$$\displaystyle{x}=-{1.69473684}$$ therefore value of x is -1.69473684 therefore the value of x rounded to two decimals is -1.69 therefore the solution of the equation rounded to two decimals is -1.69 Step 4 3) $$\displaystyle{2.15}{x}-{4.63}={x}+{1.19}$$ we have to find the solution of the equation rounded to two decimals. the given equation is $$\displaystyle{2.15}{x}-{4.63}={x}+{1.19}$$
$$\displaystyle{2.15}{x}-{4.63}={x}+{1.19}$$
$$\displaystyle{2.15}{x}-{x}-{4.63}={x}-{x}+{1.19}$$
$$\displaystyle{1.15}{x}-{4.63}={1.19}$$
$$\displaystyle{1.15}{x}-{4.63}+{4.63}={1.19}+{4.63}$$
$$\displaystyle{1.15}{x}={5.82}$$
$$\displaystyle{\frac{{{1.15}{x}}}{{{1.15}}}}={\frac{{{5.82}}}{{{1.15}}}}$$
$$\displaystyle{x}={5.06086957}$$ therefore value of x is 5.06086957 therefore the value of x rounded to two decimals is 5.06 therefore the solution of the equation rounded to two decimals is 5.06

### Relevant Questions

Find the solution of the equation rounded to two decimals.
$$8.36-0.95x-9.97$$
Find the solution of the equation rounded to two decimals.
$$3.02x+1.48-10.92$$
To find:
The solution of the equation $$8.36-0.95=9.97$$
Find the solution of the equation rounded to two decimals.
$$2.14(x-4.06)=2.27-0.11x$$
Find the solution of the equation rounded to two decimals.
$$3.95-x=2.32x+2.00$$
Find all real solutions of the equation, rounded to two decimals.
$$x^{4}-8x^{2}+2=0$$
To calculate:
The solution of the equation $$0.6p-1.9=0.78p+1.7$$ by clearing the decimals.
For digits before decimals point, multiply each digit with the positive powers of ten where power is equal to the position of digit counted from left to right starting from 0.
For digits after decimals point, multiply each digit with the negative powers of ten where power is equal to the position of digit counted from right to left starting from 1.
1) $$10^{0}=1$$
2) $$10^{1}=10$$
3) $$10^{2}=100$$
4) $$10^{3}=1000$$
5) $$10^{4}=10000$$
And so on...
6) $$10^{-1}=0.1$$
7) $$10^{-2}=0.01$$
8) $$10^{-3}=0.001$$
9) $$10^{-4}=0.0001$$
The solution of the equation $$0.36u+2.55=0.41u+6.8$$ by clearing the decimals.
Find the solution of the equation rounded to two decimals. $$\displaystyle{3.16}{\left({x}+{4.63}\right)}={4.19}{\left({x}-{7.24}\right)}$$