The rotating blade of a blender turns with constant angular acceleration 1.25 rad/s2.a) How much time does it take to reach an angular velocity of 34.0 rad/s, starting fromrest?b) Through how many revolutions does the blade turn in this time interval?

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nick1337 · Accepted Answer

a) Using equation of the motionW=W0+at&amp;nbsp;&amp;nbsp;&amp;nbsp;(1)here&amp;nbsp;W=34&amp;nbsp;rad/s,&amp;nbsp;W0=0(rest),&amp;nbsp;a=1.25&amp;nbsp;rad/s2put these value in equation&amp;nbsp;(1)34=0+1.25tt=34/1.25t=2.72&amp;nbsp;s&amp;nbsp;- Answerb) Using equation of the motionW2=W02+2aθhere&amp;nbsp;W=34&amp;nbsp;rad/s,&amp;nbsp;a=1.25&amp;nbsp;rad/s2,&amp;nbsp;W0=0342=0+2×2θθ=342/4θ=289&amp;nbsp;radsince&amp;nbsp;1&amp;nbsp;rev=2πradso number of revolutionn=θ/2π&amp;nbsp;=289/2πn=46.1&amp;nbsp;rev&amp;nbsp;- Answer

The rotating blade of a blender turns with

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