Laplace transform involving step function

$f\left(t\right)=\frac{\mathrm{sin}\left(2t\right)}{{e}^{2t}}+t\xb7u(t-4)$

Brielle James
2022-04-13
Answered

Laplace transform involving step function

$f\left(t\right)=\frac{\mathrm{sin}\left(2t\right)}{{e}^{2t}}+t\xb7u(t-4)$

You can still ask an expert for help

srasloavfv

Answered 2022-04-14
Author has **6** answers

Where

Now:

So, we get:

1. When

2. When

lildeutsch11xq2j

Answered 2022-04-15
Author has **13** answers

You can use the formula for finding the laplace transform of secondary part-

$L\left\{f\left(t\right)u(t-a)\right\}$$=L\frac{\left\{f\right(t+a\left)\right\}\times {e}^{-as}}{s}$

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