A scuba diver dove from the surface of

Answered question

2022-04-19

A scuba diver dove from the surface of the ocean to an elevation of −79

9
 
10

feet at a rate of −20 feet per minute. After spending 15 minutes at that elevation, the diver ascended to an elevation of −18

9
 
10

feet. The total time for the dive so far was 22

1
 
8

minutes. What was the rate of change in the diver's elevation during the ascent? Round your answer to the nearest hundredth.

Answer & Explanation

nick1337

nick1337

Expert2022-08-11Added 777 answers

The depth to which the scuba driver dive = -89 910 feet

The rate at which he dive = -18.9 feet/minute

The time which he spirit at that elevation =10.75 minute

The elevation the driver then ascended to = -18910feet

The total time for the dive  =1715  minutes

The time, te with which the scuba driver descanded to -89910 feet is

td=distancespeed=-89910-18.9=4.76 minutes

time,  te, the scuba driver took to elevate to -18910feet

te=1713-(4.76+10.75)=1.615 minutes

The rate of change of the drivers elevation

=final elevation-initial elevationte

=-18910-(-89910)1.615=43.96 feet/minutes

 The rate of change of the drivers elevation

=43.96 feet/minute

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