If n=110 and widehat{p} (p-hat) =0.66, construct a 95% confidence interval.Give your answers to two decimals? <p< ?

CheemnCatelvew 2020-10-25 Answered

If n=110 and p^ (p-hat) =0.66, construct a 95% confidence interval. Give your answers to two decimals ?<p<?

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lamanocornudaW
Answered 2020-10-26 Author has 85 answers

Step 1 The confidence interval for a sample proportion at 95% can be calculated using the formula, p^zp^(1p^)N<p<p^+zp^(1p^)N, where wide p^ is the sample proportion, N is the sample size and z* is the approprite value from the standard normal distributions for the desired confidence intervals. The z* value for 95% confidence interval is equal to 1.96 Step 2 The sample proportion is equal to 0.66 and the sample size is equal to 110 and the z* value is equal to 1.96 Substitute the values of p^, N and z* in the formula, p^zp^(1p^)N<p<p^+zp^(1p^)N to calculate the confidence interval of the sample proportion at 95% interval p^zp^(1p^)N<p<p^+zp^(1p^)N
0.66(1.960.66(10.66)110)<p<0.66+(1.960.66(10.66)110)
0.66(1.960.00204)<p<0.66+(1.960.00204)
0.66(1.96(0.0451)<p<0.66+(1.96(0.0451)
0.660.0884<p<0.66+0.0884
0.5716<p<0.7484 The confidence interval for the sample proportion at 95% is equal to (0.5716, 0.7484)

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