Trigonometric equation: \(\displaystyle{2}{\left({{\sin}^{{6}}{x}}+{{\cos}^{{6}}{x}}\right)}-{3}{\left({{\sin}^{{4}}{x}}+{{\cos}^{{4}}{x}}\right)}+{1}={0}\)

Ean Hughes 2022-04-09 Answered
Trigonometric equation:
2(sin6x+cos6x)3(sin4x+cos4x)+1=0
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Answers (1)

Dallelopeelvep2yc
Answered 2022-04-10 Author has 15 answers
2(sin6x+cos6x)3(sin4x+cos4x)=0
sinx=t, cos2x=1t2
2(t6+(1t2)3)3(t4+(1t2)2)=0
2(t6+13t2+3t4t6)3(t4+12t2+t4)=0
2(13t2+3t4)3(2t4+12t2)=0
(26t2+6t4)(6t4+36t2)=0
1=0
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