Question

The table shows the temperatures T (in degrees Fahrenheit) at which water boils at selected pressures p (in pounds per square inch).

Modeling data distributions
ANSWERED
asked 2021-01-25

The table shows the temperatures T (in degrees Fahrenheit) at which water boils at selected pressures p (in pounds per square inch). A model that approximates the datais: \(\displaystyle{T}={87.97}\ +\ {34.96}\ \text{In}\ {p}\ +\ {7.91}\ \sqrt{{{p}}}\) a) Use a graphing untility to plot the data and graph the model in the same veiwing window. How well does the model fit the data? b) Use the graph to estimate the pressure at which the boiling point of water is  \(300^{\circ}\) F. c) Calculate T when the pressure is 74 pounds per square inch. Verify your answer graphically.

Answers (1)

2021-01-26

a) To approximate the data \(\displaystyle{T}={87.97}\ +\ {3496}\ \text{p}\ +\ {7.91}\ \sqrt{{{p}}}\) and the table provided in the question shown below. \begin{array}{|c|c|} \hline Pressure,\ p & Temperature \\ \hline 5 & 162.24^{\circ} \\ \hline 10 & 193.21^{\circ}\\ \hline 14.696\ (1\ atm) & 212.00^{\circ}\\ \hline 20 & 227.96^{\circ}\\ \hline 30 & 250.33^{\circ}\\ \hline 40 & 267.25^{\circ}\\ \hline 60 & 292.71^{\circ}\\ \hline 80 & 312.03^{\circ}\\ \hline 100 & 327.81^{\circ}\\ \hline \end{array}ZSK Graph: Sketch the graph using graphing utility.

Step 1: Press WINDOW button to access the Window editor.

Step 2: Press Y= button.

Step 3: Enter the data \(\displaystyle{87.97}\ +\ {3496}\ \text{In}\ {p}\ +\ {7.91}\ \sqrt{{{p}}}\) which is required to graph. Step 4: Press GRAPH button to graph the function. The graph is obtained as: image Interpretation: From the graph it is observed that graph shows the curve. b) Calculate: From the above graph the pressure required is 67.29 pounds per square inch. c) Calculation: \(\displaystyle{T}={87.97}\ +\ {3496}\ \text{In}\ {p}\ +\ {7.91}\ \sqrt{{{p}}}\)
\(\displaystyle{T}{\left({74}\right)}={87.97}\ +\ {3496}\ \text{In}{\left({74}\right)}\ +\ {7.91}\ \sqrt{{{74}}}\)
\(\displaystyle{T}{\left({74}\right)}={306.4845}\)

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