What is the equation of the line tangent

Miguel Hanson

Miguel Hanson

Answered question

2022-04-08

What is the equation of the line tangent to f(x)=3x32x2+5 at x=1?

Answer & Explanation

oanhtih6

oanhtih6

Beginner2022-04-09Added 10 answers

Equation of tangent is y+13x=13
Explanation:
f(x)=3x32x2+5;x=1
f(1)=32+5=0f(1)=0 Point is 1,0
f(x)=3x32x2+5;
f(x)=9x24x
f(1)=94=13 slope is -13
The point is (1, 0) and slope of tangent is m=-13
Equation of tangent is yy1=m(xx1) or
y-0=-13(x-1) or y=-13x+13 or y+13x=13 (Ans)

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