What is the equation of the line normal

delitzo1d4

delitzo1d4

Answered question

2022-04-07

What is the equation of the line normal to f(x)=4x23x at x=1?

Answer & Explanation

titemomo8gjz

titemomo8gjz

Beginner2022-04-08Added 10 answers

Explanation:
The derivative is f'(x)=8x-3 so that f'(1)=5. The slope of the normal line is
the opposite reciprocal of this, which is 15.
Since the point (1, f(1))=(1,1) is on the line, the equation of the line is
y1=15(x1), which is equivalent to y=15(x1)+1 and
y=15x+65.

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