What is the equation of the line normal

Rubi Riggs

Rubi Riggs

Answered question

2022-04-09

What is the equation of the line normal to f(x)=132x at x=0?

Answer & Explanation

Kapovkah7hpl

Kapovkah7hpl

Beginner2022-04-10Added 14 answers

Explanation:
rewrite f(x) as f(x)=(32x)1
( using the 'chain rule' ) gives:
f(x)=1(32x)2ddx(32x)
f(x)=(32x)2(2)=2(32x)2
at x=0:f(0)=232=29
and f(0)=1/3
For perpendicular lines m1m2=1m2=129=92
equation of normal : y - b = m (x - a )
where m=92(a,b)=(0,13)
( substitute in values ) y13=92x
y=92x+13

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