I've been trying to factorise the following equation

Darian Silva

Darian Silva

Answered question

2022-04-08

I've been trying to factorise the following equation in all sorts of ways. The problem I encounter every time is not being able to do anything with the constant i.e. -20. Would any of you mind helping me with it?
2x2+xy6y26x+23y20=0

Answer & Explanation

Egerlandsq0z

Egerlandsq0z

Beginner2022-04-09Added 14 answers

An obvious start would be
(2x3y)(x+2y)6x+23y20.
Now try some educated guesses to determine a and b from
(2x3y+a)(x+2y+b)=(2x3y)(x+2y)6x+23y20,
making heavy use of ab=20. You'll end up in a=4 and b=5.

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