I'm stuck on this problem: If \(\), then

Devin Dougherty

Devin Dougherty

Answered question

2022-04-07

I'm stuck on this problem:
If ,
then find the value of:
2nk=0n1cos(2kθ)

Answer & Explanation

regulerenes4w

regulerenes4w

Beginner2022-04-08Added 10 answers

2ncosθcos2θcos22θcos2n1θ=2nsinθcosθcos2θcos22θcos2n1θsinθ=
=sin2nθsinθ=sin(πθ)sinθ=1

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