To calculate the verties and foci of the conic section:(x9)2 + (y4)2=1

Emily-Jane Bray 2021-03-07 Answered

To calculate the verties and foci of the conic section: (x9)2 + (y4)2=1

You can still ask an expert for help

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Expert Answer

au4gsf
Answered 2021-03-08 Author has 95 answers

Step 1 Formula: eccentricity (e)=1  b2a2 Step 2 Calculation: Compare this equation with the standard ellipse equation x2a2+y2b2=1 and we get: a2=81  a=9b2=16  b=4 Now, e=1  b2a2=1  1681=659 Vertices are: (± a, 0) and (0, ± b) Now, put the values of a and b to get the vertices of the conic section and we get: (± a, 0) and (0, ± b)=(± 9, 0) and (0, ± 4) Now, Foci =(± ae, 0)=(± 65, 0) Thus, the vertices and foci of the conic section are: (± 9, 0) and (0, ± 4) and (± 65, 0).

Not exactly what you’re looking for?
Ask My Question

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more