To calculate the verties and foci of the conic section:(x9)2 + (y4)2=1

Emily-Jane Bray

Emily-Jane Bray

Answered question

2021-03-07

To calculate the verties and foci of the conic section: (x9)2 + (y4)2=1

Answer & Explanation

au4gsf

au4gsf

Skilled2021-03-08Added 95 answers

Step 1 Formula: eccentricity (e)=1  b2a2 Step 2 Calculation: Compare this equation with the standard ellipse equation x2a2+y2b2=1 and we get: a2=81  a=9b2=16  b=4 Now, e=1  b2a2=1  1681=659 Vertices are: (± a, 0) and (0, ± b) Now, put the values of a and b to get the vertices of the conic section and we get: (± a, 0) and (0, ± b)=(± 9, 0) and (0, ± 4) Now, Foci =(± ae, 0)=(± 65, 0) Thus, the vertices and foci of the conic section are: (± 9, 0) and (0, ± 4) and (± 65, 0).

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