How to interpret the result according to the

Kale Bright

Kale Bright

Answered question

2022-04-06

How to interpret the result according to the table below?
Chi-square Tests Value  df  Asymptotic Significance (2-sided)  Pearson Chi-Square 2.034 Likelihood Ratio 2.033 Linear-by-Linear Association 1.380 N of Valid Cases  
a) Since 0.034<0.05, the Ho hypothesis is rejected
b) Since 0.033<0.05, the Ho hypothesis is rejected
c) Since 0.034<0.5, the Ho hypothesis is rejected
d) Since 0.380>0.05, the Ho hypothesis is accepted
e) Since 0.033<0.5, the Ho hypothesis is rejected

Answer & Explanation

llevochalecoiozq

llevochalecoiozq

Beginner2022-04-07Added 15 answers

Hypothesis testing 
For population characteristics like the population mean, population standard deviation, and so forth, hypothesis testing is done.  It is to see if the sample values agree or disagree with the original distribution's pre-stated parameter values. The hypothesis for the single population mean is conducted using the z- or t-test. The standard deviation's value affects the test that is chosen.
There are three types of chi-square tests:
Chi-square test of independence
Chi-square test of homogeneity
Chi-square goodness of fit test
Level of significance: The likelihood that a null hypothesis will be rejected in a hypothesis test when it is true.  In other words, if the value of test statistic exceeds the critical value, we conclude that the null hypothesis has been rejected.
The decision rule for the chi-square test is as follows:
In terms of test statistic--
Reject the null hypothesis if the test value falls within the rejection region; if it does not, then the null hypothesis should not be rejected.
In terms of p value--
The null hypothesis should be rejected if the p value is less than the significance level and should not be rejected if it exceeds the significance level.
Here, the Pearson's chi-square p value is 0.034. Assume that the level of significance is 0.05.
Using the decision rule as stated above,
as the p value (0.034) is less than the significance level (=0.05 ), reject the null hypothesis.
So, option a is correct.

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