Finding \(\displaystyle\lambda\) such that \(\displaystyle{\left({\ln{{\left({x}^{{2}}-{2}{x}+{2}\right)}}}\right)}^{{2}}+\lambda{\ln{{\left({x}^{{2}}-{2}{x}+{2}\right)}}}+{1}{>}{0}\forall{x}{>}{1}\)

Sebastian Fox

Sebastian Fox

Answered question

2022-04-06

Finding λ such that (ln(x22x+2))2+λln(x22x+2)+1>0x>1

Answer & Explanation

strasnihwhge

strasnihwhge

Beginner2022-04-07Added 14 answers

y2+λy+1 is a convex parable, so if you want that it is positive for y0, then it needs to have no solutions, or all the solutions must be negative.
In the first case, you need a negative discriminant, that is λ2<4. In the second case, you can solve the quadratic and impose that all the roots are negative, that is
λλ24λ+λ24<00λ24<λ
so λ must be at least positive (you could have found the same through Vieta's formulae).

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