The polar equation of the conic with the given eccentricity and directrix and focus at origin: r=41 + cos theta

alesterp 2021-01-24 Answered
The polar equation of the conic with the given eccentricity and directrix and focus at origin: r=41 + cosθ
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Brittany Patton
Answered 2021-01-25 Author has 100 answers

Step 1 If the conic of directrix x= ± p where p is positive real number and essentricity is e, and focus at origin then the polar equation of conic is: r=ep ± ecosθ

Step 2 It is provided that eccentriciti is e=1 and directrix is x=4 and focus at the origin. To find the polar equation of conic put the provided value in above equation as: r=1 × 41 ± 1 ×cosθ Since, here directrix is positive x=4 so, consider the positive sign as: r=41 + cosθ Therefore, polar equation is r=41 + cosθ

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